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Scott Dunstan
12,517 PointsResult as expected but code not accepted
The example string, and many other example strings came out as expected with this code:
def word_count(sentence):
keys_list = sentence.lower()split(' ')
new_dict = {}
for word in keys_list:
new_dict[word] = keys_list.count(word)
return new_dict
example string given was: "I do not like it Sam I Am"
so my code is called like this: word_count("I do not like it Sam I Am")
and produces this: {'am': 1, 'do': 1, 'i': 2, 'not': 1, 'it': 1, 'like': 1, 'sam': 1}
but it doesn't pass. The error message was "Hmmm, didn't get what I expected", but it is exactly what I expected! Can anyone see where I've gone wrong?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(sentence):
keys_list = sentence.lower()split(' ')
new_dict = {}
for word in keys_list:
new_dict[word] = keys_list.count(word)
return new_dict
3 Answers
Jennifer Nordell
Treehouse TeacherHi there! You're doing great, but there's part of the instructions that you're missing and I'm guessing you've only tested data sets that don't include this corner case. The challenge asks you to split the string on all whitespace. But currently you're only splitting on spaces. This does not account for whitespace such as tabs or new lines. Also, your code is missing a period/full stop between the .format() and split.
To fix this, your split should be used without any arguments. Take a look at your edited line:
keys_list = sentence.lower().split()
This will do the same thing as your code, but split on all whitespace instead of just spaces.
Hope this helps!
Scott Dunstan
12,517 PointsNever mind, I found the problem.
- I missed the "." for "split()"
- I had a literal space "split(' ')" instead of whitespace: ".split()" These dictionary challenges have messed me up
Scott Dunstan
12,517 PointsThanks Jennifer, Just posted that as you posted yours!