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Start your free trialNela Kay
11,855 PointsReturn larger number...
Hi... so, first I thought I didn't get the question, because it is quite confusing to me. But after trying out several solutions I just got stuck on the conditional. This is my code right now, but it always claims a syntax error... any ideas?
function max(3,8) {
if (parseInt(3) < parseInt(8)) {
return 8;
}
}
2 Answers
Ari Misha
19,323 Pointshiya Daniela! In real world issues, i like your approach. But you're doing way too much stuff in context of the challenge. Your function recieves two arguments and your function does a conditional to check which number is greater than the other and return it. All ya have to is return the greater number using "if else" statement. Here is my code
function max(x, y) {
if(x > y) {
return x;
} else {
return y;
}
}
blake guyan
8,297 Pointshahah, how about that for posting the exact same thing moments apart!
Ari Misha
19,323 PointsHiya blake guyan ! Haha yeah! I dont care as long as Daniela Kersting and other students gets it. (:
Nela Kay
11,855 PointsThank you both so much! I kept on trying and I finished the challenge like 20 minutes after asking the question. But with your answers I get it even more.
Thank you!!!
blake guyan
8,297 Pointsblake guyan
8,297 Pointsthose numbers are already integers... no need to parse them.
if you want to create something that works programmatically you are better off like this
function max (x, y) { if (x < y) { return y; } else { return x; } }
and then calling the function like this
max(3, 8);
so when you call the function you are telling it to compare whatever you call as the arguments rather than it just comparing something you already have numbers for :) i know thats a bit of a jump from what you are looking at, but i hope helps