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PHP Enhancing a Simple PHP Application Integrating Validation Errors Reviewing PHP Basics

Sajid Latif
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Sajid Latif
Full Stack JavaScript Techdegree Student 22,368 Points
Posted by Sajid Latif
.a{fill-rule:evenodd;}techdegree
Sajid Latif
Full Stack JavaScript Techdegree Student 22,368 Points

Return value. I think I need som { } somewhere...

Return value. I think I need som { } somewhere...

output.php 
<?php
include("flavor.php");
$flavor = return $get_flavor;
echo "Randy's favorite flavor of ice cream is ____.";

?>

2 Answers

Paolo Scamardella
Paolo Scamardella
24,828 Points
Paolo Scamardella
Paolo Scamardella
24,828 Points

It should be $flavor = get_flavor();

No need to add return since in the function it is already returning a value. Also, get_flavor is a function, so you need to add () to the end of it and no $ in front of it. It is a function, not a variable.

Variable = $name Function/Method = function_name() // calling the function/method