Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialJon Willey
6,102 PointsRuby logical operator challenge
Having trouble with this challenge. Not sure what I'm doing wrong.
def check_speed(car_speed)
if(car_speed >= 40) && (car_speed <= 50)
return = "safe"
end
check_speed()
2 Answers
Salman Akram
Courses Plus Student 40,065 PointsHi Jon,
Almost looks great but the four reasons to remove below:
- brackets
()
in first statement -
Return
- equal
=
(Ruby doesn't require to use " return = ") - add another
end
missing
def check_speed(car_speed)
if car_speed >= 40 && car_speed <= 50
"safe"
end
end
Then Everything is good :-)
Jon Willey
6,102 Pointsthanks! that worked great..