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Start your free trialAine Dunphy
3,265 PointsRuby Operators && (from novice)
As a novice, attempting to work through required Ruby task objectives. Too too much time effort/attempts have been spent on the following task objective.... much needed guidance required.
Anyone!?!?
The method below checks the speed of a car and returns a string value: either "safe" or "unsafe". Return "safe" if: The car_speed passed in as an argument is greater than or equal to the number 40. The car_speed passed in as an argument is less than or equal to the number 50. Otherwise, return "unsafe". Hint: You should use the && logical operator to accomplish this task. :)
def check_speed(car_speed)
if (car_speed >40) && (car_speed <50)
puts "safe"
else
puts "unsafe"
end
3 Answers
Steve Hunter
57,712 PointsThe question also asks for the strings to be returned, not just displayed to the screen. (And you're missing an end
too)
You can do that by just stating the string:
def check_speed(car_speed)
# write your code here
if (car_speed >= 40) && (car_speed <= 50)
"safe"
else
"unsafe"
end
end
Or you can explicitly return it using the keyword - I think it is clearer this way:
def check_speed(car_speed)
# write your code here
if (car_speed >= 40) && (car_speed <= 50)
return "safe"
else
return "unsafe"
end
end
I hope that all helps!
Steve.
Steve Hunter
57,712 PointsLooks fine but the requirements says greater and less than and equal to, so try with <= and >=
Steve.
[EDIT: attempting to get this thing to display the less than and equal to sign correctly - as soon as you use an opening HTML tag, it all goes wrong!]
[EDIT2: gives up - see the code below!]
Aine Dunphy
3,265 PointsYep - that helps a lot!!
Got it "now"
you've just renewed my faith. I can move on with a little more confidence
Next (issue)!
Steve Hunter
57,712 PointsKeep plugging away - it does become more straightforward! Ruby is a bit esoteric, at times! Just shout in the forum if you're stuck - @ mention me if you want a quick response ... I'll get that notification emailed to me.