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john larson
16,594 PointsSeemed like a bit of a merry go round here...
"available " is a string that is converted to a list "sundaes", that is converted back to a string "string". Was this done just to change the ";" to ","? Is there a more straight forward way to do this?
# string
available = "banana split;hot fudge;cherry;malted;black and white"
# string to a list
sundaes = available.split(";")
# new string with an empty var
menu = "Our available flavors are: {}."
# back to a list
string = ', '.join(sundaes)
# string of available flavors goes into the menu var
menu = menu.format(string)
3 Answers
Jennifer Nordell
Treehouse TeacherHi there john larson. As you suspected there is a slightly more direct way this can be accomplished. But I think the idea here is to make sure that you can do this so that you're set up to work with things like CSV files later down the road. I could be wrong, but it's the theory I have regarding this particular challenge.
I whipped up this code that will do the same thing, but in a little more direct way as you put it.
available = "banana split;hot fudge;cherry;malted;black and white"
menu = "Our available flavors are: {}.".format(available.replace(";", ", "))
print(menu)
edited for additional code Woops forgot the first part of the menu string! Sorry.
Hope this helps!
Chancellor Griffin
2,212 PointsHey, I recently had trouble with this challenge as well because I think the promt is a tad confusing. after task 2 I think it asks you to make that menu variable again and join it, like your line looks like here:
# back to a list
string = ', '.join(sundaes)
this can actually just be put at the end of the line. I had the same problem in my lab
# the menu variable should look like:
menu = "Our available flavors are: {}.".format(", ".join(sundaes))
and also, like I was saying before, the extra menu variable isn't needed, although the promt did mention it.
menu = menu.format(string) # not needed
So you can format using join!
Liam Cassidy
9,739 PointsFor anyone who had the same logic but is still failing:
I noticed that if you put the ", " string in a separate variable (e.g. separator = ", ") you will fail. You have to format it like John Larson did to pass:
string = ', '.join(sundaes)
john larson
16,594 PointsThat's kinda cool...I never thought about putting something like a separator in a variable, thanks