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2,179 PointsSet Math Part 2 Question
Kept getting bummer: try again... Need some help please!!
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(parameters):
course_list = []
for parameter in parameters:
for key, value in COURSES.items():
temp_parameter = {parameter, 0}
if temp_parameter.intersection(value) == {parameter}:
course_list.append(key)
else:
pass
return
return course_list
def covers_all(seta):
course_list2: []
for key, value in COURSES.items():
if seta.issubset(value):
course_list2.append(key)
else:
pass
return course_list2
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsYou are on the right path for the second task. You needed use an equal sign = instead of a colon :. Also, the else
statement is not needed if it is only going to pass
.
def covers_all(seta):
course_list2 = [] # use = instead of :
for key, value in COURSES.items():
if seta.issubset(value):
course_list2.append(key)
# else:
# pass
return course_list2
Post back if you need more help. Good luck!!