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Python Python Collections (2016, retired 2019) Sets Set Math

Set Math Part 2 Question

Kept getting bummer: try again... Need some help please!!

sets.py
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}

def covers(parameters):
    course_list = []
    for parameter in parameters:
        for key, value in COURSES.items():
            temp_parameter = {parameter, 0}
            if temp_parameter.intersection(value) == {parameter}:
                course_list.append(key)
            else:
                pass
        return
    return course_list

def covers_all(seta):
    course_list2: []
    for key, value in COURSES.items():
        if seta.issubset(value):
            course_list2.append(key)
        else:
            pass
    return course_list2

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points

You are on the right path for the second task. You needed use an equal sign = instead of a colon :. Also, the else statement is not needed if it is only going to pass.

def covers_all(seta):
    course_list2 = []  # use = instead of :
    for key, value in COURSES.items():
        if seta.issubset(value):
            course_list2.append(key)
        # else:  
        #     pass
    return course_list2

Post back if you need more help. Good luck!!