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Start your free trialMatthew Byrne
1,920 Pointssets.py
I can't see what's wrong here. Any suggestions?
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(strings):
listy = []
for course in COURSES.keys():
if strings in course:
listy.append(course)
return listy
1 Answer
Kirsten Smith
3,484 PointsSince you are using sets, it would be easier to compare the lists of courses if you used set math, aka an INTERSECTION to perform the check rather than if __ in ____.
Cheo R
37,150 PointsCheo R
37,150 PointsLooks like in you example, you're checking if the contents of strings is founds in your COURSES.keys().
If the value I pass in were to be, 'taco', listy would return an empty list. If the value I pass n were to be, 'Python', 'listy', would return a list with one item, ['Python Basics'].
But that's not what the question is asking. The question is asking to return a list of course name(s) if the contents of strings is founds in any of the sets for each course. So strings, might not be a string, but say, a list/set. Compare everything in that list/set with the sets for each course, and if there's items that overlap, add that course name to listy.
So you'd want to get something like