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Sabaa Talal
Courses Plus Student 733 Pointsskipping items if it is start with "a"!!
this is the question (Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".) I tried this codes but it did not work can you help me figure out what is wrong with it?? Sincerely,,
def loopy(items):
# Code goes here
for thing in items:
if (thing).index[0]=='a':
continue
else:
print (thing)
2 Answers
Steve Hunter
57,712 PointsHi there,
You're pretty close with that. There's no need to use the word index, though. You can access the first element of the current iteration by just using square brackets, like thing[0]. And you don't need to surround thing in parentheses, except for the print part. The rest is correct.
Steve.
Michael Hulet
47,913 PointsIn Python, when we say "index", we mean a number that represents a specific place in a list. lists on their own have no property or method named index, and to get an object from a specific index in a list, you just use the subscript with the proper list name directly, like this:
some_list = ["This", "is", "a", "list"]
string = some_list[0] # string is now equal to "This"
To be clear, all the information above also applies to strs, so if you're trying to get a character at a specific index of a string, the same syntax will work