slices

Question

make a function named odds that accept an iterable as an argument and returns the items with an odd index in the iterable.

im stuck guyz

slices.py

def first_4(iterable):
  return iterable[0:4]

first_4([66, 333, 222, 1, 1234])

Answer 1 · 2014-12-18T09:26:53Z

December 18, 2014 9:26am

Ok, what you want to do is to make the slice start at 1, since it's the first odd number:

def odds(iterable):
   return iterable[1:       #Starting at position 1

You want it to run to the end, so you don't add a stop:

def odds(iterable):
   return iterable[1::      #No stoping until the end of the list

You want to take two steps every time, so:

def odds(iterable):
   return iterable[1::2]     #Step is two, so we get 1, 3, 5, 7 etc.

Should do it.

Answer 2 · 2015-03-28T01:10:40Z

March 28, 2015 1:10am

it is work for me

def first_4(iterable):
  return iterable[0:4]+ iterable[45:50]

def odds(iterable):
  return iterable[1::2]

Answer 3 · 2016-08-17T05:55:34Z

August 17, 2016 5:55am

My code is this, but still I'm getting error : Oops! It looks like Task 1 is no longer passing. def first_4(list1): return list1[:4]

def odds[list2]: return list2[1::2]

Answer 4 · 2014-12-17T10:34:08Z

December 17, 2014 10:34am

some_iterable[(start position inclusive):(end position exclusive):(step length, i.e. 1 takes every number, 2 takes every second number etc.)]

Answer 5 · 2014-12-18T08:16:43Z

December 18, 2014 8:16am

def odds (iterable): return iterable [0:1]

its failing to work guys, how have you go about it.

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