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Start your free trialRonald Tse
5,798 PointsSo confused with this part...
So confused with pack & unpack.
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
dict = [{"name": "Ronald", "food": "tacos"}, {"name": "Peter", "food": "Shit"}]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(name=None, food=None):
result_list = []
for items in dict:
result_list.append(template.format(**dict))
return result_list
Alexander Davison
65,469 PointsYes. It still would cause errors. You can;t use that as a name. ;)
1 Answer
john larson
16,594 Pointsdef string_factory(name=None, food=None): # need a dict parameter
result_list = []
for items in dict: # dict might not work, it is a keyword
result_list.append(template.format(**dict)) # maybe format items
return result_list
Alexander Davison
65,469 PointsActually, dict is a function :)
john larson
16,594 Pointsjohn larson
16,594 PointsThank you Alex, I knew it was something. So would using dict as a variable cause problems in this case?