solution

Hi Akhil,

In this challenge you nee to record the floated values before you add them together in order to get the code to work in challenge 3 of 3. If you float the numbers in the return statement you won't be able to separate them later and have the challenge except the answer.

  def add(num1, num2):
    num1 = float(num1);
    num2 = float(num2);
    return num1 + num2; 

Then in challenge 3 or 3 you will be able to test that the numbers are not strings in the try: and then return the floated values if the numbers are integers.

def add(num1, num2):
    try:
        num1 = float(num1);
        num2 = float(num2);
    except ValueError:
        return None
    else:
        return num1 + num2;

You're close, but I think you are over thinking a little. There is no need to convert to an int() as in the 'try' block. It is asking to try and add together 2 numbers that are converted into floats. So, in the parameters (a and b), there should always be numbers. If the parameters are passed strings or anything that can't be converted to a float, you would get the ValueError. So in the 'except' block should return None. The else statement in this situation is not needed.

No need to overthink this one. In the try block, assume everything works. Then in the except block just do as the question asks, and return None

def add(a,b):
    try: return float(a) + float(b)
    except ValueError: return None