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PHP PHP Basics Daily Exercise Program Conditionals

Waqas Munir
Waqas Munir
1,103 Points

Solving an if else statement.

Question: Check if each student has a GPA of 4.0. If the student has a GPA of 4.0, use the student's name variable to display "NAME made the Honor Roll". If not, use the variable to display "NAME has a GPA of GPA". Code: <?php $studentOneName = 'Dave'; $studentOneGPA = 3.8;

$studentTwoName = 'Treasure'; $studentTwoGPA = 4.0;

//Place your code below this comment if($studentOneGPA == 4.0){ echo "$studentOneName made the Honor Roll. \n"; } else { echo "$studentOneName has a GPA of $studentOneGPA. \n"; } if($studentTwoGPA == 4.0){ echo "$studentTwoName made the Honor Roll. \n"; } else { echo "$studentTwoName has a GPA of $studentTwoGPA."; } ?>

What is wrong with my code?

index.php
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
if($studentOneGPA == 4.0){
  echo "$studentOneName made the Honor Roll. \n";
}
else {
  echo "$studentOneName has a GPA of $studentOneGPA. \n";
}
if($studentTwoGPA == 4.0){
  echo "$studentTwoName made the Honor Roll. \n";
}
else {
   echo "$studentTwoName has a GPA of $studentTwoGPA.";
}
?>

if($studentOneGPA == 4.0) { echo "$studentOneName made the Honor Roll"; } else { echo "$studentOneName has a GPA of $studentOneGPA "; }

if($studentTwoGPA == 4.0) { echo "$studentTwoName made the Honor Roll"; } else { echo "$studentTwoName has a GPA of $studentTwoGPA "; }

2 Answers

Waqas Munir
Waqas Munir
1,103 Points

What was actually wrong that did not let me solve the problem? Can you please explain? It will help me.

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points

Hey there Waqas Munir

The reason it wasn't passing was because PHP likes the else statement to be on the same line and right after the closing brace of the if statement.

Have a look at this post I just answered for another student.