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Oprea Mihai
5,592 Pointsstats
I can't figure out last part of this task: Can you help me ?
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(name):
return len(name)
def num_courses(name):
i = 0
for value in name.values():
i += len(value)
return i
def courses(name):
course_list = []
for value in name.values():
for course in value:
course_list.append(course)
course_list = set(course_list)
return course_list
def most_courses(name):
list_teach={}
for key ,value in name.items():
course_l=len (value)
nb_course = course_l
list_teach.update({key: nb_course})
list_teach=max(list_teach.items() , key=lambda k:k[1])
list_teach=list_teach[0]
return list_teach
def stats(name):
list_teach = {}
list_2=[]
for key, value in name.items():
course_l = len(value)
#nb_course = course_l
list_1=[key,course_l]
list_2.append(list_1)
list_teach.update(list_2)
return list_teach
1 Answer
Stuart McIntosh
Python Web Development Techdegree Graduate 22,874 PointsHi there, your very nearly there I think. Does the below make sense?
def stats(t_dict):
s_list = [] # create the list to return
for k in t_dict.keys(): # iterate through the passed in dict keys
s_list.append([k, len(t_dict[k])]) # append the key (teachers nane and the len of the key value)
return s_list