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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Posted by Mauro Bonucci
Mauro Bonucci
5,953 Points

Status Server 200

Cant pass this challenge, somethings is wrong, i leave my code above:

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4){
    xhr.readyState === 200)
  }


};
xhr.open('GET', 'sidebar.html');
xhr.send();

3 Answers

Dave McFarland
STAFF
Dave McFarland
Treehouse Teacher
Dave McFarland
Dave McFarland
Treehouse Teacher

Hi Mauro Bonucci

You need to check that the readyState is 4 AND that the status is 200. That requires using a conditional statement with an AND operator like this:

if (xhr.readyState === 4 && xhr.status === 200) {

}
Robert Bojor
PLUS
Robert Bojor
Courses Plus Student 29,439 Points
Robert Bojor
Robert Bojor
Courses Plus Student 29,439 Points

Hi Mauro,

You have an extra ) right after 200, plus you don't set the readyState to 200, no point for that. Check the code below

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4){ /* Do whatever logic is needed */ }
};
xhr.open('GET', 'sidebar.html');
xhr.send();
Mauro Bonucci
Mauro Bonucci
5,953 Points
Mauro Bonucci
Mauro Bonucci
5,953 Points

Your right :-S, thanks Robert