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Ruby Ruby Basics (Retired) Ruby Methods Method Returns: Part 2

Mark Miller
Mark Miller
45,831 Points

Still, no way through this quiz, Method Returns: Part 2 (Ruby Basics)

Will someone please reveal the code for this quiz?

Neil Anuskiewicz
Neil Anuskiewicz
11,007 Points

Hi Mark, what quiz do you mean?

3 Answers

Gavin Ralston
Gavin Ralston
28,770 Points

In the previous challenge, we wrote a method that returned the remainder of two arguments when divided. That's cool, but it would be nicer if the method returned the remainder in a nice full sentence. Use string interpolation to return the remainder inside the sentence “The remainder of a divided by b is c.” where a is your “a” variable, b is your “b” variable, and c is the value of a % b.

Okay, so... you're working with string interpolation, which just means replacing placeholders in your string with some other values you already have stored in variables (passed into your method, or created inside of it, in this case).

Here's an example that isn't exactly like what the challenge asks for, but is comparable and should make a good template for you to get your head around it:

def add(a, b)
  c = a + b
  "The sum of #{a} plus #{b} is #{c}."
end

In the example above, you're just plugging the values stored at a, b, and c, whatever they might be, right into the string by replacing them when you return the string from the method.

...and, since Ruby will return the last statement in a method automatically, that string will get returned. You can always add a return statement in front of the string if it's easier to read.

One specific "gotcha" on this challenge if you understood all that already is this: watch the punctuation in the challenge text -- There's a sneaky little "." character at the end of that sentence that I find hard to see with the current font weight in the challenges.

Thanks this was driving me crazy :D. Good tip about that period it's easy to miss. And i didn't know you needed to define c.

Gavin Ralston
Gavin Ralston
28,770 Points

Well, you don't have to define c, you could just plug "a + b" into the last placeholder. :)

oh ok cool. yeah i was trying that at first but i think i was missing that last period when i was using a % b as placeholder.

Akin Soyleyen
Akin Soyleyen
3,579 Points

That was keeping me awake for 2 days.