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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Joelle Kruczek
Joelle Kruczek
1,375 Points

still stuck - moved the while loop

I moved the while loop. I thought I fixed the indent correctly - this is v frustrating.

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

    while start
        rnum = random.randit(1,99)
         if even_odd(rnum):
            print("[]" is even".format(rnum))
        else:
            print("[]" is odd".format(rnum))
        start -=1

1 Answer

reanimator313
reanimator313
6,005 Points
reanimator313
reanimator313
6,005 Points

Indent the while loop outside the function

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:  # mist ":"
    rnum = random.randint(1,99)  # is randint not randit
    if even_odd(rnum):
        print("{} is even".format(rnum))  # for placeholder use "{}"
    else:
        print("{} is odd".format(rnum))  # for placeholder use "{}"
    start -= 1
Joelle Kruczek
Joelle Kruczek
1,375 Points

I fixed the errors that you pointed out, thank you. But I still get - the first = IMPORT RANDOM - Task 1 is no longer passing.

I saw references to moving the while loop under the function, and I thought with the indents that this is what I did. now I am confused.

reanimator313
reanimator313
6,005 Points

I edit my post. "randint" not "randit". I did not see that :)

Joelle Kruczek
Joelle Kruczek
1,375 Points

import random

start = 5

def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2

while start:
    rnum = random.randint(1,99)
    if even_odd(rnum):
        print(""{}" is even".format(rnum))
    else:
        print(""{}" is odd".format(rnum))
    start -=1

am still getting the Task 1 not found error

reanimator313
reanimator313
6,005 Points

your code

if even_odd(rnum):
    print(""{}" is even".format(rnum))
else:
    print(""{}" is odd".format(rnum))

my code

if even_odd(rnum):
    print("{} is even".format(rnum))
else:
    print("{} is odd".format(rnum))

the placeholder don't need special quotes

Joelle Kruczek
Joelle Kruczek
1,375 Points

if I change to

if even_odd(rnum): print("{} is even".format(rnum)) else: print("{} is odd".format(rnum))

I get the Bummer! Wrong number of prints. error.

reanimator313
reanimator313
6,005 Points

I tried this code and it works

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    rnum = random.randint(1,99)
    if even_odd(rnum):
        print("{} is even".format(rnum))
    else:
        print("{} is odd".format(rnum))
    start -= 1