Storing the returned value of the function in a new variable named yearToday

Question

Step 1: Create a function named getYear

function getYear () {

}

Step Two: add this variable to the functions code block, var year = new Date().getFullYear();

function getYear () {
   var year = new Date().getFullYear();
};

Step 3: This is where I am getting stuck... "Call the getYear function: store the returned value of the function in a new variable named yearToday.

function getYear () { 
   var year = new Date().getFullYear();
};
var getYear = yearToday;

or

should my code just simply be:

function getYear () { 
    var getYear = yearToday;
};

Do I even need the "var year = new Date().getFullyear();" code block that was asked of me in step 2? I don't know why but this JS is getting the best of me:-( Thanks in advance! Sorry if my question is in disarray with the syntax, just getting frustrated with JS at 1:10 am EST and I have to wake up in 4 hours. BLAH!!

script.js

index.html

<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

Answer 1 · 2016-08-30T05:28:52Z

August 30, 2016 5:28am

Hi Jason,

I think you are overthinking this one!

Simply ask yourself what is it that the function is returning. Try it out in a console (even your browser's, or a website like JSfiddle). Ultimately, the function is returning the full year of a newly created Date object (which will be our current year). You can read more about Date here.

This is the information that the function has returned, but the next step is asking you to store the information called with the getYear() function in a new variable, yearToday. You can achieve this like so:

function getYear(){
 var year = new Date().getFullYear();
 return year;
}

var yearToday = getYear();

Happy coding! Leslie

Answer 2 · 2016-08-30T05:27:41Z

August 30, 2016 5:27am

function getYear () {
   var year = new Date().getFullYear();
   return year;
};

Your function also need to return the value

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Jason Hess

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Storing the returned value of the function in a new variable named yearToday

2 Answers

Leslie Heinzen

Leslie Heinzen

Thomas Nilsen

Thomas Nilsen