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Start your free trialYeeka Yau
7,410 Pointsstring_factory takes one positional argument, but 2 given
Hi, my string_factory function works in workspaces, but fails in the challenge module:
def string_factory(dict_list):
string_list = []
for dict in dict_list:
string = "Hi, I'm {name} and I love to eat {food}!"
string = string.format(**dict)
string_list.append(string)
return string_list
Thanks for any help in advance!
dicts = [
{'name': 'Michelangelo',
'food': 'PIZZA'},
{'name': 'Garfield',
'food': 'lasanga'},
{'name': 'Walter',
'food': 'pancakes'},
{'name': 'Galactus',
'food': 'worlds'}
]
string = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(dict_list):
string_list = []
for dict in dict_list:
string = "Hi, I'm {name} and I love to eat {food}!"
string = string.format(**dict)
string_list.append(string)
return string_list
1 Answer
Yeeka Yau
7,410 PointsWoops, nevermind, misread the question - it requires the function to take a string and a list.