string_factory.py

Question

It just says  Bummer! 'name'     ????? I am not sure what I am doing wrong! I have try more than one approach and I can't unpack at the bottom, because it marks it incorrect too. I appreciate the help.
```string_factory.py
Example:
values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
string_factory(values)
["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
def stringfactory(name=None, food=None):
    while True:
        name=name
        food=food
        if name and food:
            return template.format(name, food)
stringfactory({"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"})        
```

Andrew Wilcox · Answer

Dear Mark,
Thanks for the feedback. I already solved the problem. 
appreciate it!
Best,
Andrew

Mark Rinkel · Answer

Hey, there's a couple issues in your code. 
Your function needs to take a list of dictionaries as it's input. Let's call those values. 
python
def string_factory(values):

It asks us to return a new list of strings, so lets start by making an empty list
python
   newStrings = []

Since we need to perform an action for each value passed to the function, lets use a loop. Then we can access the name and food properties of the dictionary individually. 
python
  for value in values:
      name = value["name"]
      food = value["food"]

And then we can use the format() function to create our string and append it to our newStrings list.
python
  formattedString = template.format(name=name, food=food)
  newStrings.append(formattedString)

Lastly we will return our newStrings list. Here's what my code looks like all together.
```python
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(values):
  newStrings = []
  for value in values:
      name = value["name"]
      food = value["food"]
        formattedString = template.format(name=name, food=food)
        newStrings.append(formattedString)
  return newStrings;
```

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Andrew Wilcox

Andrew Wilcox

string_factory.py

2 Answers

Mark Rinkel

Mark Rinkel

Andrew Wilcox

Andrew Wilcox