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Python Python Basics (2015) Shopping List App Continue

Posted by oshayne anderson
oshayne anderson
839 Points

stuck at skip while using loop

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
    # Code goes here
    if 'a' == [0]
        continue
    else:
gabrielabazan
gabrielabazan
14,153 Points

Hello,

I'd suggest telling it what to do if it's not 0 first, then tell it to continue through or skip if 0. (Flip your if/else statement). Hope that helps.

1 Answer

Stuart Wright
Stuart Wright
41,119 Points
Stuart Wright
Stuart Wright
41,119 Points

If the function is called 'loopy', perhaps it should contain a loop :)

After that, you need to check if the first character of each item in the loop is 'a' - see line 3 for the correct syntax for that.

def loopy(items):
    for item in items:
        if item[0] == 'a':
            continue
        else:
            print(item)
Sean Pooley
Sean Pooley
4,934 Points
Sean Pooley
Sean Pooley
4,934 Points

Thanks, Stuart. I'd spent about an hour trying figure this out! Didn't even cross my mind to use a for loop before the if statement!