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Victor Katsande
3,094 PointsStuck for days on this one, where am i going wrong
the whole question for the task is below
I want you to try and reproduce it yourself.
First, import the random library.
Then create a function named random_item that takes a single argument, an iterable. Then use random.randint() to get a random number between 0 and the length of the iterable, minus one. Return the iterable member that's at your random number's index.
Check the file for an example.
import random
def random_item(iterable)
random_number = random.randint(0, len(list(iterable))-1)
return iterable[random_number]
1 Answer
Ken Alger
Treehouse TeacherVictor;
A couple of things here.
1) You are missing a colon after your def statement.
2) Can you tell me why you are converting your iterable to a list?
Ken
Alexander Davison
65,469 PointsAlexander Davison
65,469 PointsThe colon obviously is a problem, but I don't see why he shouldn't convert
iterableto a list. Even after converting it to a list, it would return the same length. It only wouldn't work if the iterable is a dictionary, but that is unlikely because it doesn't make sense to "return a random value" from a dictionary. Is the value a key? Or is it a value? :/Ken Alger
Treehouse TeacherKen Alger
Treehouse TeacherSometimes the challenge checking engine is pretty picky about what it is looking for and submitting code that "works" doesn't pass.
Alexander Davison
65,469 PointsAlexander Davison
65,469 PointsOh. I see.
Chris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsRegarding the use of
list(). It is necessary in the case of a dict. All iterables should return a valid value in response tolen(). Sets, strings, tuples, list, and even dicts, all have lengths. For dicts, the length is the number of keys. Unfortunately, a random number in the range of the length is unlikely to be a valid key when trying to return a value. So by converting the keys to a list, passing a dict to the function still works to return a random key.That said, I don't believe the checker tests with a dict argument.
I would submit that if one's code meets the description of the challenge but doesn't pass then either the challenge description needs refining or the checker needs updating. We have recently seen valid code fail a different challenge. In that case the checker needed updating.
Nobody should have to guess at how the checker might misinterpret their code.
In this case, having code that's more robust than the checker requires seems fine.
Great job Victor!