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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Tomáš Drtil
Tomáš Drtil
1,024 Points

Stuck in this Challange even when I'm getting the same result

Why am I not able to pass?

def word_count(string): dict_string_updated = {} splitted_string = string.lower().split(" ") for word in splitted_string: dict_string_updated[word] = dict_string_updated.get(word, 0) + 1 return dict_string_updated

print(word_count("I do not like it Sam I Am"))

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    dict_string_updated = {}
    splitted_string = string.lower().split(" ")
    for word in splitted_string:
        dict_string_updated[word] = dict_string_updated.get(word, 0) + 1
    return dict_string_updated


print(word_count("I do not like it Sam I Am"))

1 Answer

Brennan White
Brennan White
11,646 Points

I had the same issue. You are splitting on " ", which is just a space - not all white space. Use split().