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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Hussein Amr
Hussein Amr
2,461 Points
Posted by Hussein Amr
Hussein Amr
2,461 Points

stuck on the code challenge as always

any ideas on how i should proceed?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(*args).lower():
    word = "I am a good kid am I not"
    word = list(word)
    for string in word:

1 Answer

dojewqveaq
dojewqveaq
11,393 Points

Hey!

The python word = list(word) is returning a list of the chars in the variable word.

You should try the split() method. For example:

sentence = "My name is Eric"
words_in_sentence = sentence.split()
print words_in_sentence

This will print out ['My', 'name', 'is', 'Eric']

Hint: sentence.lower().split() will return ['my', 'name', 'is', 'eric']