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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by Michael Gallego
Michael Gallego
1,568 Points

Stuck on this challenge. Don't know how to delete all occurrences of the vowel.

If anyone can help me out on this problem, that would be great. Thanks.

disemvowel.py 
def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u"]
    word = word.lower()
    list_of_word = list(word)

    for x in vowels:
        try:
            list_of_word.remove(x)
        except ValueError:
            continue
        else:
            print(list_of_word)
    word = "".join(list_of_word)
    return word

1 Answer

Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer
Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer

Hi Micheal Your code contains everything to pass but somethings are unnecessary ex.

    list_of_word = list(word)

The word,string by default it's a list instead we can create an empty list

    list_of_word = []

The word argument shouldn't be changed ex.

    word = word.lower()

The try method it's not needed for this quiz. The for loop should actually loop trough the word argument, like so:

for x in word:

Now after this you should check if the x variable it's not in the vowels list

for x in word:
    if x.lower() not in vowels:       <--- now it should be lowered to match with the "vowels" list --->

From here it's clear that if it's not in vowels it must go in the empty list

for x in word:
    if x.lower() not in vowels:
        list_of_word.append(x)         <---- without the lower() method to actually return the original letter --->
word = ''.join(list_of_word
return word

Or you could return the joined list without setting to a variable

return ''.join(list_of_word)

I hope it will help you out.Happy coding