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2,006 PointsStuck on word_count quiz...
"Create a function named word_count() that takes a string. Return a dictionary with each word in the string as the key and the number of times it appears as the value."
What I have so far I think is close, but I am not really sure. This is my first time programming so I am honestly a little lost but am seeing a little improvement already haha. What should I do to fix this, or should I scrap it and start over? Ideas? Thank you!
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(string):
new_string = string.split()
my_dict = {}
for key in my_dict:
if key in new_string:
count += 1
my_dict[key] = new_string
else:
break
word_count
1 Answer
man odell
1,905 Pointsdef word_count(string):
try to create new array to collect the words by index and other array for the count with index that match the #words array index - you can use <any_array>.append(<the value EX s[for loop count]>)> method to add value #to your array
new_string = string.split() my_dict = {} for key in my_dict: if key in new_string: count += 1 my_dict[key] = new_string else: break
word_count