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Python Python Basics (2015) Number Game App Squared

syntax error

can anyone tell me where the indentation should be ?

squared.py
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(s):
    try:
        int(s)
        if int(s) is int:
            return (int(s)**2)
        else:
            return (s * len(s))

1 Answer

Antonio De Rose
Antonio De Rose
20,885 Points
def squared(s):
    try:
        s = int(s)#conversion of the integer needs to be saved into a variable
        #if int(s) is int:#was not sure about this part
        return (s ** 2)
    except:#I changed your else to except
        return (s * len(s))

Just a sidenote, but when catching exceptions, you should always be as definite as possible, because otherwise the program might "swallow" errors which you do not actually expect. (So writing except ValueError would be a better practice in this case.)