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Ruby Ruby Operators and Control Structures Logical Operators The And (&&) Operator

Ariel Espinal
Ariel Espinal
5,451 Points
Posted by Ariel Espinal
Ariel Espinal
5,451 Points

Syntax error on line 15 when i don't even have a line 15? Ruby

I seems to be missing something in my code, can't seem to wrap my head around it...

Question was:

The method below checks the speed of a car and returns a string value: either "safe" or "unsafe". Return "safe" if: The car_speed passed in as an argument is greater than or equal to the number 40. The car_speed passed in as an argument is less than or equal to the number 50. Otherwise, return "unsafe". Hint: You should use the && logical operator to accomplish this task. :)

My Code:

def check_speed(car_speed)
  if (car_speed >= 40) && (car_speed <= 50)
    puts "safe"
  else
    puts "unsafe"
  end

3 Answers

Rafael Capati
Rafael Capati
10,725 Points

Hi Ariel, you have to close the function check_speed with a end keyword. The last end in your code is closing the if statement, but there is one missing for the function.

def check_speed(car_speed)
  if (car_speed >= 40) && (car_speed <= 50)
    puts "safe"
  else
    puts "unsafe"
  end
end # <-- Missing end
Ariel Espinal
Ariel Espinal
5,451 Points
Ariel Espinal
Ariel Espinal
5,451 Points

Ah! Good eye! However, i'm trying to submit my answer but I'm receiving a communications error. I could only assume the server is expecting another way to write it.

Coleman Kelly
Coleman Kelly
889 Points
Coleman Kelly
Coleman Kelly
889 Points

I'm actually having an issue with this challenge as well. It keeps telling me I need to make I return safe. Here's my code:

def check_speed(car_speed)
  if (car_speed >= 40) && (car_speed <= 50)
    puts "safe"
  else
    puts "unsafe"
 end
end
Ariel Espinal
Ariel Espinal
5,451 Points
Ariel Espinal
Ariel Espinal
5,451 Points

Yea i'm receiving a communications error now trying to submit it. :(

Rafael Capati
Rafael Capati
10,725 Points

I see, you have to return the value back to the call function, for that you have to use the return keyword instead of the puts method.

def check_speed(car_speed)
  if (car_speed >= 40) && (car_speed <= 50)
    return "safe" # return the value
  else
    return "unsafe" # return the value
 end
end
Coleman Kelly
Coleman Kelly
889 Points
Coleman Kelly
Coleman Kelly
889 Points

Ah, that worked. I remember Jason talking about if/else/elsif and case/when but I don't remember return being mentioned in any of the videos prior to that challenge. Thanks for the help!