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Jen Farrant
6,905 Pointstakes 0 positional arguments but 1 was given
This code passes in Thonny (when I use 'print' instead of 'return'), but fails in the code challenge with 'TypeError num_teachers takes 0 positional arguments but 1 was given.
Despite Googling all the key terms I do not understand what this error code is telling, and I don't understand why it works outside of the code challenge.
please help!
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
teachers = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
'Kenneth Love': ['Python Basics', 'Python Collections'],'Jane Smith':['Flask basics', 'Django Basics']}
def num_teachers():
total_teachers = list(teachers.keys())
return(len(total_teachers))
num_teachers()
2 Answers
Stuart Wright
41,120 PointsYou received this error because the function you defined does not take any arguments, but the challenge expects it to take one argument (the dictionary of teachers). You simply need to include teachers as an argument to your function, like this:
def num_teachers(teachers):
total_teachers = list(teachers.keys())
return(len(total_teachers))
Jen Farrant
6,905 PointsThanks Stuart - I thought I had tried that, but I was obviously doing it wrong.
that is now working !