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Bruce Caraway
5,961 PointsTask 1 works fine until I start working on Task 2. The problem is not in Task 1 and I can't get any feedback on Task2.
How do I get the grader to look at my "new" Task 2 code?
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(teachers):
max_count = 0
max_teacher = ''
teacher_class_count = {}
for key in teachers:
teacher_count = 0
if key in teacher_class_count:
teacher_count = teacher_class_count[key]
teacher_class_count[key] = teacher_count
if teacher_class_count[key] > max_count:
max_count = teacher_class_count[key]
max_teacher = key
else:
teacher_class_count[key] = 1
if max_teacher =='':
max_teacher = key
max_count = 1
return max_teacher
def num_teachers(teachers):
teacher_count = 0
teachers_counted = []
for key in teachers:
if key not in teachers_counted:
teachers_counted.append(key)
teacher_count += 1
return teacher_count
2 Answers
Keerthi Suria Kumar Arumugam
4,585 PointsThere is a small flaw in your algorithm for task 1. If you look closely, you can see that the first "if" block inside your for loop is never executed. I have modified your algorithm slightly in the code below. Your code for the second task looks clean though. Check it out.
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(teachers):
print(teachers)
max_count = 0
max_teacher = ''
for key in teachers:
if max_teacher == '' or max_count < len(teachers[key]):
max_teacher = key
max_count = len(teachers[key])
return max_teacher
def num_teachers(teachers):
teacher_count = 0
teachers_counted = []
for key in teachers:
if key not in teachers_counted:
teachers_counted.append(key)
teacher_count += 1
return teacher_count
Bruce Caraway
5,961 PointsAh, yes - thanks Keerthi!