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Shadow Skillz
3,020 PointsTask 4
Not sure how to get the teachers with the most classes.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dic):
return len(dic)
def num_courses(dic):
course = 0
for teachers in dic:
course += len(dic[teachers])
return course
def courses(dic):
class1 = []
for classes in dic.values():
class1.extend(classes)
return class1
def most_courses(dic):
max_count = 0
teachers = " "
for teach, m_courses in dic.iterems():
if m_courses > (max_count):
max_count = len(m_courses)
teachers = teach
return teachers
2 Answers
james south
Front End Web Development Techdegree Graduate 33,271 Pointsyou are close, just need to tweak a few things. in your loop, the (a) proper dict method is items, not iterems. then in your if statement, you want to compare the length of the values to max, not the values themselves. you are updating max correctly, but the next line is indented wrong. tab it over right once to be under the max_count = len(m_courses) line, so the teacher to be returned is only updated if max is also updated. otherwise the return value is simply the last teacher in the loop. after these changes i think it will work. edited after passing to show while iteritems is a dict method, the challenge will throw an error, so use items.
Gabor Kovacs
4,874 Pointsdef most_courses(ts):
for t,c in ts.items():
if max(c):
return t
Shadow Skillz
3,020 PointsShadow Skillz
3,020 Pointsthanks for the reply James but I'm still having issues. It's telling me (TypeError: unorderable types: str() > int()) can you provide some visual assistance i would appreciate it.