Task 4: Checked independently--will get back teacher with max count of classes!!

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict1):
    list1 = (list(dict1.keys()))
    return(len(list1))

def num_courses(dict1):

    list2 = (list(dict1.values())) 
    flat_list = []
    for sublist in list2:
        for item in sublist:
            flat_list.append(item)
    return(len(flat_list))

def courses(dict1):

    list2 = (list(dict1.values())) 
    flat_list = []
    for sublist in list2:
        for item in sublist:
            flat_list.append(item)
    return(flat_list)

def most_courses(dict1):

    list4 = list(dict1.items()) 
    max_count = []
    len_val_iterable = 0

    i = 0
    for tup in list4:
        tup = list4[i:i+1]
        tup_pop = tup.pop()
        tup_val = list(tup_pop[1:])
        flat_list = []
        for sublist in tup_val:
            for item in sublist:
                flat_list.append(item)
        len_val = len(flat_list)

        if len_val > len_val_iterable:
           len_val_iterable = len_val
           max_count = tup_pop[0:1]
        elif len_val == len_val_iterable:
           max_count = max_count + tup_pop[0:1]
        i +=1