task 5 of 7 build a simple php application

Azumi,

The instructions could've been a little more explicit here, but the issue is that you are still echoing $flavor1 and $flavor2 inside your foreach loop, when instead, you should be echoing the temporary variable $flavor that your foreach loop has created to hold each value of your array as it loops over them.

<?php foreach ( $flavors as $flavor ) { ?>
    <li><?php echo $flavor; ?></li>
  <?php } ?>

Erik

Azumi,

I have been developing in PHP for a while and I found the way that question is arranged to be extremely confusing. I got it to pass using the following code:

<?php

    $flavors = ["Chocolate", "Vanilla", "strawberry"];

?>
<p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors); ?> flavors of ice cream.</p>
<ul> 
<?php
foreach($flavors as $flavor){
    echo "<li>" . $flavor . "</li>";
}
?>
</ul>

Long story short, your code is fine and this is a bug. You should end statements with semi-colons like Erik McClintock said, but the reason that code would not fire is because you have a line break after <?php echo count($flavors);?> and "flavors of ice cream."

Hope this helps.

Thank you, Stephen. I would have been stuck on this step for hours.... It is formatted differently than how the instructor advised to write such code in the video example...