Teachers and classes challenge

Can you walk us through your thought process for the above code? I think I see where you're going, but I'm not certain.

This step of the challenge wants you to give back the name of the teacher with the most classes, so you need a way to keep track of the current high scoring teacher and that high score as you loop through the dictionary. Also, .value() doesn't exist, you want .values() if you just want the values from the dictionary (you probably want .items() instead, though).

Okay, I will try to explain what I'm having problem with...

1st I define a function called

most_classes(teachersDic):

2nd I have to make empty variables that's going to hold my

teachers_list = []
classes_list  = []
max_count = [] 
teacher_with_max_count = []

3rd I loop in teachersDic to find out my teachers_list

for teachers in teachersDic:

we get teachers_list = [teachers]

but from here I'm stuck, how do I get individual teacher as variable with classes number, I know to get classes number I have to do: len(classes_list), however that will give me back the list of numbers.

also to compare the values can I use <, >, ==, <=, >= like in C code? If no, how should I compare the values to find out the largest?

To answer your last question first, yes, you can compare with <, >, ==, <=, and >= just like in C.

We loop through a dictionary just like we do a list, but each step is only the key, not the key and the value. To get the value of a key, we have to ask the dictionary for it. So, for example, if I have a dict named teachers and a key named 'Kenneth Love', I can get the value for that key with teachers['Kenneth Love'].

In our challenge, each key (teacher's name) has a list of classes. So when I get teachers['Kenneth Love'], I'm getting a list, which I can find the length of by using len(). The basic start of the challenge's solution is:

def most_classes(teachers):
    high_classes = 0
    high_teacher = ''

Now, loop through teachers, and on each step get the length of that teacher's classes (not the length of the teacher's name, be sure to get the value from the dictionary). If that length is higher than the current high_classes variable, change high_classes and change high_teacher to that teacher's name. When you've gone through all of the teachers, return high_teacher.

I'm doing the Challenge Task 4 of 4

"Write a function named courses that takes the dictionary of teachers. It should return a list of all of the courses offered by all of the teachers."

With this code I get an error: "Bummer! You returned 5 courses, you should have returned 18." However when I run the test on Sublime it does the trick.

my code:

def courses(teachers_list):
  all_courses = []
  all_courses.extend(teachers_list.values())
  return all_courses

when I try to loop, like so:

def courses(teachers_list):
  all_courses = []
  for course in teachers_list.values():
  all_courses.extend(course)
  return all_courses

it returns courses one by one, with every next one adding the previous and with last one it gives the right result. How do I skip the adding process and get the result?

For exp:

teachers = {'Jo': ['a1', 'a2', 'a3', 'a4', 'a5'], 'Mo': ['s1', 's2', 's3', 's4'], 'Lol': ['d1', 'd2']}
list_all = []

for list_of_classes in teachers.values():
    list_all.extend(list_of_classes)
    print (list_all)

in return I get this:

['s1', 's2', 's3', 's4']
['s1', 's2', 's3', 's4', 'a1', 'a2', 'a3', 'a4', 'a5']
['s1', 's2', 's3', 's4', 'a1', 'a2', 'a3', 'a4', 'a5', 'd1', 'd2']

the last thing it gives back is our right answer, however since it's looping through the dictionary the program adds values one by one from each key.