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Start your free trialadriantennison
3,090 Pointsteachers.py
Can anyone help me in the fourth task
Im returning 5 instead of 18
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(teachers):
counts = []
max_classes = 0
for key in teachers:
counts.append(len(teachers[key]))
for value in counts:
if value > max_classes:
max_classes = value
for key in teachers:
if max_classes == len(teachers[key]):
return key
def num_teachers(teach_dict):
teach_count = 0
for name in teach_dict:
teach_count += 1
return teach_count
def stats(teachers):
total_stats = []
for teacher in teachers:
total_stats.append( [teacher, len(teachers[teacher])] )
return total_stats
def courses(teachers_dict):
course = []
for list_of_classes in teachers_dict.values():
course.extend(teachers_dict.values())
return course
1 Answer
Ryan S
27,276 PointsHi Adrian,
You are almost there. The challenge wants a single list of all the courses taught. As you have it right now, you are looping through the dictionary values and creating a list of lists (Remember that list_of_classes is a list, not a single item). You just need to go one step further and pull out the items from each of those lists. For this you can use another nested for
loop.
Good luck.