teachers.py task 2

Question

ive tried this question but my return counts the number of lists in a list. Can anyone help me?

question: That one wasn't too bad, right? Let's try something a bit more challenging. Create a new function named num_courses that will receive the same dictionary as its only argument. The function should return the total number of courses for all of the teachers.

teachers.py

# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.


def num_teachers (dictofteachers):
    return len(dictofteachers)

def num_courses(dictofteachers):
    listofvalues = dictofteachers.value()
    return len(listofvalues)

Answer 1 · 2017-03-29T18:38:23Z

March 29, 2017 6:38pm

Try this

def num_courses(dic):
    number = []
    for v in dic.values():
        number += v
    return len(number)

Answer 2 · 2017-03-27T17:59:22Z

March 27, 2017 5:59pm

one way is to use the dict.items() method, which allows you to loop through the keys and values of a dict, like for k,v in myDict.items(): you can then access properties of the keys and values and do what you need to do.

Answer 3 · 2018-04-03T09:53:11Z

April 3, 2018 9:53am

def num_courses(teachesr): courses = [] for course in teachesr.values(): courses += course return len(courses)

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Royce Sithole

Royce Sithole

teachers.py task 2

3 Answers

Opanin Akuffo

Opanin Akuffo

james south

james south

ALFRED SIBANDA

ALFRED SIBANDA

Rusell Shamu

Rusell Shamu