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Ian Cruz
4,186 PointsTeacherStat challenge. I dont understand what to do from here
this question is sizzling my brain, i dont understand what i am supposed to do and how im supposed to write it.guaaah
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
teacher = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
def most_classes(teacher):
most_classes = 0
for keys in teacher.values:
1 Answer
Andreas cormack
Python Web Development Techdegree Graduate 33,011 PointsHi Ian
This is how i did it.
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
# first way of doing it
def most_classes(mydic):
max_classes =None # string to hold the max count of classes
teacherWithMaxClasses=None # this string will hold the teacher with maximum classes
classes=[] # i use this list as a holder for the list of teachers classes, this then helps me use the max function to get the list with the maximum classes in it
for value in mydic.values():
classes.append(len(value))
max_classes=max(classes)
for key,value in mydic.items(): # I then compare if the length of each list to the max_classes variable and if they are equal that means that key and value must be the teacher with the maximum classes, i then add key aka the name to the teacherWithMaxClasses variable.
if len(value)==max_classes:
teacherWithMaxClasses=key
return teacherWithMaxClasses
# second way of doing it
def most_classes(mydic):
newdict = {}
for key, value in mydic.items():
newdict[len(value)]= key # swap the values for keys
return newdict[max(newdict.keys())] # then call the max function passing in the dictionary keys which will return the key aka the value with the maximum count
hope this helps
Ian Cruz
4,186 PointsIan Cruz
4,186 PointsHey thanks your help, i tried implementing your code and i even tried straight up copying and pasting it in but it's not working. it keeps saying "Bummer!
most_classes()returned {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations']}, expected 'Jason Seifer'. Sorry if im missing something simple, im still trying to figure out the logic in programming through my brain haha but thanks again for your helpAndreas cormack
Python Web Development Techdegree Graduate 33,011 PointsAndreas cormack
Python Web Development Techdegree Graduate 33,011 PointsHi Ian
Apologies I ran the code locally and it worked, but forgot to check what the challenge was asking. Try my code now and it should pass. Basically my code was returning a dictionary of the teacher with the maximum classes rather than just the teachers name, hence the challenge did not pass. In terms of programming logic it comes with practice, also try to come up with the solution in more of a practical sense, once you have found that practical solution then try putting it into code. It also helps to pay more attention to the problem at hand rather then jumping to the solution.
hope this helps