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PHP

Posted by Shafeeq Ahmed
Shafeeq Ahmed
6,058 Points

ternary operator

My code is,

$num_1 = 9; $num_2 = 9;

define("NUM_3",23); define('NUM_4',78);

$numbers = array(345,23,97,25,4);

echo $num_1 <= $num_2 and NUM_3 >= NUM_4 ? "Yes": "No";

It suppose to print "Yes" or "No" to the page. Instead it prints 1 to the page. Can anyone explain this to me please.

1 Answer

Chuck Emory
Chuck Emory
14,476 Points
Chuck Emory
Chuck Emory
14,476 Points

First, if you trying to trying determine if $num_1 = NUM_4, you need to use == (equal comparison operator) instead of =. Right now you're saying you want $num_1 to be the same as NUM_4. At said, when I test your code using the == it echoes back 'No' like it should. If you are getting anything else, you may have something else in your code causing the issue. Try pulling out just the code you're having issue with and using a PHP tester (like http://phptester.net/) to help evaluate your code.