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jalil damian
1,452 PointsThat one wasn't too bad, right? Let's try something a bit more challenging. Create a new function named num_courses
a
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(teachers):
count = 0
for teacher in teachers:
count += 1
return count
def num_courses(course):
total = 0
for courses in course.total():
total += 1
return total
1 Answer
Tonye Jack
Full Stack JavaScript Techdegree Student 12,469 PointsLolz these are easy one liners for speed
num_teachers = lambda arg: len(arg.keys())
num_courses = lambda arg: sum([len(c) for c in arg.values()])
courses = lambda arg: [c for s in arg.values() for c in s]
most_courses = lambda arg: [t for t, c in sorted(arg.items(), key=lambda a: len(a[1]), reverse=True)][0]
stats = lambda arg: [[t, len(c)] for t, c in arg.items()]
frankgenova
Python Web Development Techdegree Student 15,616 Pointsfrankgenova
Python Web Development Techdegree Student 15,616 PointsI found the use of the len() helpful. Each key has a list as a value. And therefore the length of each list is the number of courses. When you iterate (loop) through the dictionary of teachers you can count the items in each list where the list is the value of the a specific key.