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Start your free trialLarissa Rose
27,681 PointsThe And (&&) Operator Code Challenge
The method below checks the speed of a car and returns a string value: either "safe" or "unsafe". Return "safe" if: The car_speed passed in as an argument is greater than or equal to the number 40. The car_speed passed in as an argument is less than or equal to the number 50. Otherwise, return "unsafe". Hint: You should use the && logical operator to accomplish this task. :)
def check_speed(car_speed)
def check_speed(car_speed)
if (car_speed >= 40) && (car_speed <= 50)
return "safe"
else
return "unsafe"
end
end
Larissa Rose
27,681 PointsOh, I didn't even realize I did that.
3 Answers
Paul Ryan
4,584 PointsRemove the first def, you do not need two and remove the brackets from your first if
Rachelle Wood
15,362 PointsThe () can be used in the if statement. The code and the challenge will still work.
Paul Ryan
4,584 Pointsmust just be the multiple methods at the top so
Rachelle Wood
15,362 PointsAssuming you have your variable car_speed declared
def check_speed(car_speed)
if(car_speed >= 40) && (car_speed <= 50)
return "safe"
else
return "unsafe"
end
end
Larissa Rose
27,681 PointsThank you! I got it now...It didn't pass because I declared the method twice.
Rachelle Wood
15,362 PointsYeah it is easy to do things like that in Ruby. I have done that too. That and forgetting to put the right amount of ends in.
Luis Senior
10,432 Pointswhy does it need two Ends? I never saw that in any previous videos
Scott Andersen
Courses Plus Student 10,244 PointsYou have two things to 'end' there. The first 'end' ends the if/else block, and the second one ends the loop itself.
Rachelle Wood
15,362 PointsRachelle Wood
15,362 PointsOut of curiosity, why do you have the method declared twice?