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Start your free trialFrank Hoke
8,651 PointsThe code makes a list of lists for stats, but ....
I've written code several ways that will make a list of lists that works, but it doesn't like something because it gets rejected, maybe the formatting? Am I missing something obvious?
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.def most_classes(teachers_dict):
teachers_dict = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],'Kenneth Love': ['Python Basics', 'Python Collections']}
def most_classes(teachers_dict):
maxcount = 0
newcount =0
for teacher in teachers_dict:
newcount =len(teachers_dict[teacher])
if newcount > maxcount:
maxcount = newcount
max_teacher = teacher
return max_teacher
def num_teachers(teachers_dict):
number = len(teachers_dict.keys())
return number
def stats(dicts):
stats_list = []
for key, value in dicts.items():
item = "{},{}".format(key, int(len(value))).split(",")
stats_list.append(item)
return stats_list
Dan Johnson
40,533 PointsIf you're still having issues with the challenge post your updated code and I'll go over it.
2 Answers
Dan Johnson
40,533 PointsWith the method you're using, the course count is of type str when a type of int is expected.
Instead of dealing with a str conversion and back, you could go right for the list:
item = [key, len(value)]
Frank Hoke
8,651 PointsFound another approach that was accepted as correct:
Frank Hoke
8,651 PointsFrank Hoke
8,651 PointsThanks. Tried that and still get a lists of lists, but it still says "didn't get the expected output". The answer looks like what is being asked for, so I'm unsure why it is being rejected.