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PHP Enhancing a Simple PHP Application Integrating Validation Errors Reviewing PHP Basics

The flavor.php include file contains a function named get_flavor. That function receives no arguments, and it returns a

Please help guys

output.php
<?php
include('flavor.php'); 
echo "Randy's favorite flavor of ice cream is ____.";

?>

2 Answers

Hi Tinashe,

You just need to create a variable named flavor and set it equal to the returned value from get_flavor.

<?php
include('flavor.php');
$flavor = get_flavor();
echo "Randy's favorite flavor of ice cream is ____.";
?>
Allen Brown
Allen Brown
32,515 Points

The challenge asks you to call the function get_flavor, and then assign the return value to a variable named flavor. Remember in php that variable names start with a '$'. After your include line, name the variable, and then set it equal to the call to the function get_flavor.