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Nicholas Gaerlan
9,501 PointsThis answer works so... I don't know what to do
Do I need to use a more complicated method where I build a list by iterating over all the elements in courses w/ values that intersect with the given argument. That's exactly what the comprehension does so... I feel like I'm giving the most Pythonic and easy to read solution. Open to any ideas
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(topics):
return [x for x in COURSES if COURSES[x] & topics]
def covers_all(topics)
return [x for x in COURSES if topics == COURSES[x] & topics]
3 Answers
Joe Beltramo
Courses Plus Student 22,191 PointsThis should be giving you a syntax error around line 20,
def covers_all(topics) // You are missing a colon :
Nicholas Gaerlan
9,501 Pointsomg... can't believe i missed that
Nicholas Gaerlan
9,501 Pointsfunny thing is... the way covers_all is written should work for the first part of the challenge (except of course renaming the function to covers instead of covers_all) but the quiz won't accept it as an answer