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Elizabeth Chipendo
Courses Plus Student 6,468 PointsThis block of code displays two sentences related to flavors of ice cream. In this code challenge
we'll modify the code block to use a variable and a conditional. First, create a new variable named flavor and assign your favorite flavor as the value. (Add this command at line 2. Don't forget to use a dollar sign in the variable name, and don't forget to end your command with a semi-colon.)
<?php
<?php $flavor = "mint";
echo "Your favorite flavor of ice cream is "; echo $flavor; echo ".";
echo "vanilla";
echo ".</p>";
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
if($flavor=="cookie dough") echo "Randy's favorite flavor is cookie dough, also!";
?>
2 Answers
Tommy Bregar
10,847 PointsNot sure what your question is, but you need to remove that second "<?php" and make a couple changes to your "echo" commands - as you go through the steps of the challenge you need to replace sections of the code, not just add to it so your code looks like:
<?php
$flavor = "mint";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough") {
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>
Furquan Ahmad
5,148 PointsThe syntax of your code is wrong, make sure your doing an if statement correctly.
if($flavor=="cookie dough")
{
echo "Randy's favorite flavor is cookie dough, also!";
}