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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by Abhishek Dhakla
Abhishek Dhakla
6,177 Points

This code seems to work when I test on individual cases but is failing here, help?

Please check the issue with it

disemvowel.py 
def disemvowel(word):
    temp = list(word)
    new = ''
    for letters in temp:
        if letters.lower() == 'a' or letters.lower() == 'e' or letters.lower() == 'i' or letters.lower() == 'o' or letters.lower() == 'u':
            continue
    else:
        new += str(letters)
    return new

1 Answer

Brendan Whiting
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.a{fill-rule:evenodd;}techdegree seal-36
Brendan Whiting
Front End Web Development Techdegree Graduate 84,738 Points
Brendan Whiting
.a{fill-rule:evenodd;}techdegree seal-36
Brendan Whiting
Front End Web Development Techdegree Graduate 84,738 Points

It's an intending problem. Your else block needs to be indented the same as your if block, otherwise it ends up working differently.

def disemvowel(word):
    temp = list(word)
    new = ''
    for letters in temp:
        if letters.lower() == 'a' or letters.lower() == 'e' or letters.lower() == 'i' or letters.lower() == 'o' or letters.lower() == 'u':
            continue
        else:
            new += str(letters)
    return new
Abhishek Dhakla
Abhishek Dhakla
6,177 Points

Thanks a lot, didn't notice this small error