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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Bruce Röttgers
Bruce Röttgers
18,211 Points
Posted by Bruce Röttgers
Bruce Röttgers
18,211 Points

This code should work, is it my fault or the challenge's?

Hey there, I wrote this code for the linked challenge (it should split on all whitecaps and count how often a word lowercased appears). I checked it against the example and three random strings and it works on my local machine. Though, I still get the false output error in the challenge, what am I doing wrong?

Thanks, Bruce.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(arg):
    arg = arg.lower()
    words = arg.split(" ")
    words_dict = {}
    for word in words:
        num = words.count(word)
        words_dict[word] = num
    return words_dict

1 Answer

Philip Schultz
Philip Schultz
11,437 Points
Philip Schultz
Philip Schultz
11,437 Points

Hello, Your code will work if you take the quotations out of the split method. Just leave it blank. more info on split below https://stackoverflow.com/questions/743806/how-to-split-a-string-into-a-list