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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by JD Vila
JD Vila
8,095 Points

This code works in command line, but not on Treehouse

So even though this brings the desired results in my terminal Python environment, Treehouse says that my code is wrong. Please help!

Code:

def word_count(sentence): my_sentence = sentence.lower() my_dict = {} sentence_list = my_sentence.split(" ") for word in sentence_list: if word in my_dict: my_dict[word] = int(my_dict[word]) + 1 else: my_dict[word] = 1 return my_dict

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentence):
    my_sentence = sentence.lower()
    my_dict = {}
    sentence_list = my_sentence.split(" ")
    for word in sentence_list:
        if word in my_dict:
            my_dict[word] = int(my_dict[word]) + 1
        else:
            my_dict[word] = 1
    return my_dict

1 Answer

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're very close on this one! The key here is having it split on all whitespace. My guess is that you haven't tried running this code with any strings that contain tab characters and newline characters. Those are also whitespace.

Currently, your code is splitting on all spaces, but it should be splitting on all whitespace including tabs and newlines. So, if I change just one teensy thing, your code passes.

To split on all spaces we use split(" "), but to split on all whitespace we use just split() with no arguments.

When I remove the arguments in split(), your code passes with flying colors! All in all, well done! :sparkles:

JD Vila
JD Vila
8,095 Points

Thank you so much, Jennifer! Appreciate the pointer!