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Start your free trialRouillie Wilkerson
10,419 PointsThis isn't working, and keeps resulting in a syntax/parse error:
This is my code, and it's not working!
function max(6,12) { if(6<12) { return 12;} else { return 6;} }
function max(6,12) {
if(6<12) {
return 12;}
else {
return 6;}
}
1 Answer
scribbles
21,173 PointsYou need to give the parameters names:
function max(firstNumber, secondNumber) {
if (firstNumber > secondNumber) {
return fistNumber;
}
return secondNumber;
}
When you call the function you could pass through the values of 6 and 12 like so:
max(6, 12); // Returns 12
Rouillie Wilkerson
10,419 PointsRouillie Wilkerson
10,419 PointsI spent nearly two days trying to figure this out. Now I get it. Thanks very much for your help. I completed the challenge!