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Python Python Collections (Retired) Slices Slice Functions

Posted by Spencer Johnson
Spencer Johnson
19,708 Points

This works for me, when I test it in Workspaces, but it is throwing an error????? Is this also a correct option?

in workspaces, I am adding 'print' in front of first_4(20) and it is printing back the 1st four [0, 1, 2, 3] in the range of 20. So why is this failing the coding challange...

def first_4(i): iterable = list(range(i)) return iterable[:4]

first_4(20)

slices.py 
def first_4(i):
  iterable = list(range(i))
  return iterable[:4]

first_4(20)

1 Answer

William Li
PLUS
William Li
Courses Plus Student 26,868 Points
William Li
William Li
Courses Plus Student 26,868 Points

Hi, Spencer

in workspaces, I am adding 'print' in front of first_4(20)

No, the argument for this function needs to be an iterable, 20 is not; iterables in Python are list, string ....

the answer is actually pretty simple.

def first_4(i):
  return i[:4]   # slice out the first 4 items in the iterable
Spencer Johnson
Spencer Johnson
19,708 Points

Thank you

Spencer Johnson
Spencer Johnson
19,708 Points

Thank you, I changed it to code below and then tested in workspaces and it passed. 

def first_4(i):
  return i[:4]

print(first_4(list(range(20))))