Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Sets Set Math

This works in a regular environment...

This works as designed, but I cannot get it to pass the browser test.

sets.py
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}
def covers(item):
    course_list = []
    for k, v in COURSES.items():
        if item.issubset(v):
            course_list.append(k)
    return course_list

2 Answers

Steven Parker
Steven Parker
231,275 Points

This does something a bit different from what the instructions ask for. They want a list of every overlap, not just complete subsets. An "overlap" would be any case where the intersection was non-empty.

You might want to keep this idea in reserve though .. it could be handy for the next task.

Ah, yes. Thank you! intersection has done the trick and the next challenge - well that's solved ;)